Which kind of problems occur in dining philosopher?
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Which kind of problems occur in dining philosopher?
The dining philosopher’s problem is the classical problem of synchronization which says that Five philosophers are sitting around a circular table and their job is to think and eat alternatively. A bowl of noodles is placed at the center of the table along with five chopsticks for each of the philosophers.
How do you solve the dining philosophers problem?
A solution of the Dining Philosophers Problem is to use a semaphore to represent a chopstick. A chopstick can be picked up by executing a wait operation on the semaphore and released by executing a signal semaphore.
What is the critical section problem in the dining philosophers problem?
The Solution of the Dining Philosophers Problem The critical section is a segment of the program that allows you to access the shared variables or resources. In a critical section, an atomic action (independently running process) is needed, which means that only single process can run in that section at a time.
What is dining philosopher problem and how can it be solved using mutex locks?
To address this problem, we may consider each chopstick as a shared item protected by a mutex lock. Each philosopher, before he can eat, locks his left chopstick and locks his right chopstick. If the acquisitions of both locks are successful, this philosopher now owns two locks (hence two chopsticks), and can eat.
What is the problem if all Dining Philosophers simultaneously pick up their left fork explain?
If every philosopher picks up the left fork at the same time, noone gets to eat – ever. Some other suboptimal alternatives: Pick up the left fork, if the right fork isn’t available for a given time, put the left fork down, wait and try again.
How does starvation occur in dining philosophers problem?
Dining Philosophers, with N=4. The problem is how to design a discipline of behavior (a concurrent algorithm) such that no philosopher will starve; i.e., each can forever continue to alternate between eating and thinking, assuming that no philosopher can know when others may want to eat or think.
How can we prevent starvation in dining philosophers problem?
No starvation: Since a hungry philosopher p always keeps p’s clean chopsticks, and since each of p’s neighbors must deliver their shared chopstick to p, cleaned, either immediately (if the neighbor is thinking) or as soon as that neighbor finishes eating, then we conclude that a hungry philosopher p cannot be passed up …
How can we prevent deadlock in dining philosophers problem?
The waiter solution to Dining Philosophers Strategy: Every philosopher must request each of their (shared) chopsticks from a waiter, who may refuse the request at first in order to avoid a deadlock. For convenience, we assume that all philosophers request their left chopstick first, then their right chopstick.
Why the philosophers are eating spaghetti in dining philosophers problem?
Their philosophical problem in this instance is that the dish served is a kind of spaghetti which has to be eaten with two forks. There is a fork between each plate. Each philosopher can only alternately think and eat. Moreover, a philosopher can only eat their spaghetti when they have both a left and right fork.
Can Dining Philosophers result in starvation?
How can we avoid the deadlock in the dining philosophers problem?
How do Dining Philosophers prevent deadlock?
What is deadlock and starvation?
Starvation occurs when one or more threads in your program are blocked from gaining access to a resource and, as a result, cannot make progress. Deadlock, the ultimate form of starvation, occurs when two or more threads are waiting on a condition that cannot be satisfied.
Can deadlock occur in dining philosophers problem?
The philosopher can only use the chopstick on his or her immediate left or right. The philosophers never speak to each other, which creates a dangerous possibility of deadlock. Deadlock could occur if every philosopher holds a left chopstick and waits perpetually for a right chopstick (or vice versa).
How many semaphores are used in dining philosophers problem?
two semaphores
Semaphore Solution to Dining Philosopher – There are three states of the philosopher: THINKING, HUNGRY, and EATING. Here there are two semaphores: Mutex and a semaphore array for the philosophers. Mutex is used such that no two philosophers may access the pickup or putdown at the same time.
What is starvation in dining philosopher?
What is the problem if all Dining Philosophers simultaneously pick up their left fork?
In our previous solution, the deadlock is caused by having every philosopher to pick up his left chopstick. This produces a circular waiting. If this circular waiting can be broken, deadlocks will go away. To this end, we can force on of the philosophers to act differently.
How can we prevent deadlock in dining philosopher?
How can we prevent starvation in Dining Philosophers Problem?
What is starvation problem?
Starvation is the problem that occurs when low priority processes get jammed for an unspecified time as the high priority processes keep executing. A steady stream of higher-priority methods will stop a low-priority process from ever obtaining the processor.